Solve equation I, II and III and answer the following questions.

I.(10x² + (P + Q)x + 10) = (x² + 4)

II.3y² + (P + Q - 4)y + 10 = 0

III. 3z² + (P - Q)z - 104 = (2z² - 6)

Note:

i) One of the roots in equation I is -2 and one of the roots in equation III is 7.

If the smallest root in the equation II is added to the last two digit prime number. Find 50% of the reduced number.