The ratio of the amount of 'Petrol' to 'Diesel' in a container is 409 : 629 respectively. If 51.9 liters of the mixture is taken out from the container and mixed with 20.1 liters of another mixture of 'Petrol' to 'Diesel' (in which the amount of 'Diesel' is 'Z' liters) in such a way that after selling the mixture at the cost price of  'Petrol', the profit percentage earned is 20%. If the cost price of 'Petrol' to 'Diesel' is 80 Rs./L and 60 Rs./L respectively then find the value of 20Z?