Given below there are three number series (I, II, and III). The wrong(Odd one out) number of series (I, II, and III) is (A, B, and C) respectively. Find the value which establishes the correct relationship between A, B, and C.
Series I: 92, 194, 591, 2372, 11865, 71208
Series II: 4096, 256, 32, 8, 4, 16, 8
Series III: 846, 944, 1144, 1444, 1844, 2344
1
B x C < A
2
A / C > B
3
A - B = C + 11003
4
(B)3 + (C x 2) = A - 6075
5
None of the above