Direction: These questions are based on the following information.

There are Seven members Babita, Beenu, Beeru, Bittu, Bhashkar, Bashu and Bhanu are in a family and each have different number of chocolates 2, 6, 8, 15, 3, 17, and 12. The one who is having chocolates equal to perfect cube of a number is father of Babita. Babita and Bhanu are sisters. The one who have total number of chocolates is multiple of 4 is husband of Bhanu. Bittu is Bhanu's husband. Bhashkar is niece of Babita. Beenu is maternal grandmother of Bhashkar. Bashu who doesnot have even number of chocolates is mother-in-law of Bhanu. The one who is in third generation have highest number of chocolates. Total number of chocolates of Bhanu is sum of the total chocolates of Bittu and Bashu. Total number of chocolates of Babita is more than the chocolates of Beenu and less than the total chocolates of Beeru.