Two tangents in the circle x2 + y2 = 4 at the point A and B meet at the point P(-4, 0). Then the area of the quadrilateral PAOB, O being the origin, is
1
\(2\sqrt{3}\) sq. units
2
\(8\sqrt{3}\) sq. units
3
\(4\sqrt{3}\) sq. units
4
\(6\sqrt{3}\) sq. units