Let \( y = y(x) \) be the solution of the differential equation \( \sin x \dfrac {dy}{dx} + y \cos x = 4x, x \epsilon (0, \pi) \). If \( y \left ( \dfrac { \pi }{ 2 } \right ) = 0 \), then \( y \left ( \dfrac { \pi }{ 6 } \right ) \) is equal to

1
\( -\dfrac {8}{9} \pi^{2} \)
2
\( -\dfrac {4}{9} \pi^{2} \)
3
\( \dfrac {4}{9 \sqrt {3}} \pi^{2} \)
4
\( \dfrac {-8}{9 \sqrt {3}} \pi^{2} \)

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