Matrices of order 3 × 3 are formed by using the elements of the set A = (-3, -2, -1, 0, 1, 2, 3}, then probability that matrix is either symmetric or skew symmetric is:
1
\(\frac{1}{7^6}+\frac{1}{7^3}\)
2
\(\frac{1}{7^9}+\frac{1}{7^3}-\frac{1}{7^6}\)
3
\(\frac{1}{7^3}+\frac{1}{7^9}\)
4
\(\frac{1}{7^3}+\frac{1}{7^6}-\frac{1}{7^9}\)