A voltage of 50 sin 1000 t V is applied across a parallel plate capacitor with plate area of 5 cm2 and plate separation gap of 5 mm. If the dielectric material the capacitor has ε = 2 ε0, then the capacitor current will be (in amperes)
1
\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\cos {10^3}t\)
2
\({\varepsilon _0}{10^4}\cos {10^3}t\)
3
\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\sin {10^3}t\)
4
\({\varepsilon _0}{10^4}\sin {10^3}t\)