Let P(A) = \(\frac{7}{13}\), P(B) = \(\frac{9}{13}\) and P(A ∩ B) = \(\frac{4}{13}\). Then P(A' ∣ B) is equal to

1
\(\frac{6}{13}\)
2
\(\frac{4}{13}\)
3
\(\frac{4}{9}\)
4
\(\frac{5}{9}\)

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