In a tournament, there are twelve players S1, S2, ..., S12 and divided into six pairs at random. From each game a winner is decided on the basis of a game played between the two players of the pair. Assuming all the players are of equal strength, then
| List – I | List – II |
|---|---|
| (I) Probability that S2 is among the losers is | (P) 5/22 |
| (II) Probability that exactly one of S3 and S4 is among the losers is | (Q) 1/2 |
| (III) Probability that both S2 and S4 are among the winners is | (R) 6/11 |
| (IV) Probability that S4 and S5 not playing against each other is | (S) 10/11 |
| (T) 3/11 |
Which is correct option?
1
(I) → Q , (II) → R , (III) → P , (IV) → T
2
(I) → Q , (II) → T , (III) → P , (IV) → S
3
(I) → Q , (II) → P , (III) → R , (IV) → S
4
(I) → Q , (II) → R , (III) → P , (IV) → S