Calculate the emf of a cell at 298 K for the reaction:
Ni(s) + 2Ag+ → Ni2+ + 2Ag(s)
(Ecell∘ = 1.05 V, [Ag+] = 0.001 M, [Ni2+] = 0.160 M)
1
1.12 V
2
0.90 V
3
1.00 V
4
1.08 V
Calculate the emf of a cell at 298 K for the reaction:
Ni(s) + 2Ag+ → Ni2+ + 2Ag(s)
(Ecell∘ = 1.05 V, [Ag+] = 0.001 M, [Ni2+] = 0.160 M)