A manufacturing company makes two models M1 and M2 of a product. Each piece of M1 requires 9 labour hours for fabricating and one labour hour for finishing. Each piece of M2 require 12 labour hours for fabricating and 3 labour hours for finishing. For fabricating and finishing, the maximum labour hours available are 180 and 30 respectively. The company makes a profit of Rs. 800 on each piece of M1 and Rs.1200 on each piece of M2
The above Linear Programming Problem [LPP] is given by
Maximize Z = 800x + 1200y
Subject to constraints,
3x + 4y ≤ 60
x + 3y ≤ 30
x, y ≥ 0
Maximize Z = 800x + 1200y
Subject to constraints,
3x + 4y ≥ 60
x + 3y ≥ 30
x, y ≥ 0
Maximize Z = 800x + 1200y
Subject to constraints,
3x + 4y ≤ 60
x + 3y ≥ 30
x, y ≥ 0
Maximize Z = 800x + 1200y
Subject to constraints,
3x + 4y ≥ 60
x + 3y ≤ 30
x, y ≥ 0