If the foot of the perpendicular from point (4, 3, 8) on the line \({L_1}:\frac{{x - a}}{l} = \frac{{y - 2}}{3} = \frac{{z - b}}{4}\), l ≠ 0 is (3, 5, 7), then the shortest distance between the line L1 and line \({L_2}:\frac{{x - 2}}{3} = \frac{{y - 4}}{4} = \frac{{z - 5}}{5}\) is equal to:
1
\(1 \over \sqrt6\)
2
\(1 \over 2\)
3
\(1 \over \sqrt3\)
4
\(\sqrt {2 \over 3}\)