If x4 + y4 = 16, then find the second derivative of y.

1
y" = \(\frac{32x^2}{y^5}\)
2
y" = \(\frac{-48x^2}{y^7}\)
3
y" = \(\frac{-24x^2}{y^7}\)
4
y" = \(\frac{-48x^3}{y^5}\)

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