The feasible solution for an LPP is shown in Figure. Let Z = 3x – 4y be the objective function.
(Maximum value of Z + Minimum value of Z) is equal to:1
13
2
1
3
–13
4
–17
The feasible solution for an LPP is shown in Figure. Let Z = 3x – 4y be the objective function.
(Maximum value of Z + Minimum value of Z) is equal to: