If \(\left[\begin{array}{ll} 2 & 1 \\ 3 & 2 \end{array}\right] \cdot A \cdot\left[\begin{array}{cc} -3 & 2 \\ 5 & -3 \end{array}\right]=\left[\begin{array}{cc} 1 & 0 \\ 0 & 1 \end{array}\right]\), then A =
1
\(\left[\begin{array}{ll} 1 & 1 \\ 1 & 0 \end{array}\right]\)
2
\(\left[\begin{array}{ll} 1 & 1 \\ 0 & 1 \end{array}\right]\)
3
\(\left[\begin{array}{ll} 1 & 0 \\ 1 & 1 \end{array}\right]\)
4
\(\left[\begin{array}{ll} 0 & 1 \\ 1 & 1 \end{array}\right]\)