Let y : (\(\sqrt{2/3}\), ∞) → ℝ be the solution of

(2x − y)y′ + (2y − x) = 0, y(1) = 3.

Then

1
y(3) = 1
2
y(2) = 4 + \(\sqrt{10}\)
3
y ′ is bounded on \((\sqrt{2/3}, 1)\)
4
y′ is bounded on (1, ∞)

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