In Burkitt’s Lymphoma, a reciprocal translocation between chromosome 8 and 14 is observed. If an individual is heterozygous for this translocation, the consequence in meiosis will be as follows:

A. Four chromosomes, i.e., normal chromosome 8 and 14, and translocated chromosomes 8 and 14, pair together

B. The two normal chromosomes 8 and 14, and two translocated chromosomes pair separately

C. All gametes produced from this meiosis are non-viable as they have deletions and duplications

D. In one of the cross configurations called "alternate segregation" all gametes having normal or translocated chromosomes, survive

E. The gametes having normal chromosomes only survive while all gametes having translocated chromosomes are non-viable, hence the translocations are used as crossover suppressors

Which of the following combinations best describes the meiotic consequences for the translocation described above?