If x2 + y2 = t − \(\frac{1}{\text{t}}\) and x4 + y4 = t2 + \(\frac{1}{\text{t}^{2}}\), then \(\frac{dy}{dx}\) equals :

1
\(\frac{−1}{x^{3}y}\)
2
\(\frac{1}{x^{3}y}\)
3
\(\frac{1}{x^{2}y}\)
4
\(\frac{1}{xy}\)

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