The position vector of a moving body at any instant of time is given as \(\overrightarrow{\mathrm{r}}=\left(5 \mathrm{t}^{2} \hat{\mathrm{i}}-5 \mathrm{t} \hat{\mathrm{j}}\right) \mathrm{m}\). The magnitude and direction of velocity at t = 2s is,
1
\(5 \sqrt{15}\) m/s, making an angle of tan–1 4 with –ve Y axis
2
\(5 \sqrt{15}\) m/s, making an angle of tan–1 4 with +ve X axis
3
\(5 \sqrt{17}\) m/s, making an angle of tan–1 4 with –ve Y axis
4
\(5 \sqrt{17}\) m/s, making an angle of tan–1 4 with +ve X axis