Let \(\left[\varepsilon _{0}\right]\) denote the dimensional formula of the permittivity of vacuum. If \(M\) = mass, \(L\) = length, \(T\) = time and \(A\) = electric current, then:
1
\(\left[\varepsilon _{0}\right]=\left[M^{-1}L^{-3}T^{4}A^{2}\right]\)
2
\(\left[\varepsilon _{0}\right]=\left[M^{-1}L^{2}T^{-1}A^{-2}\right]\)
3
\(\left[\varepsilon _{0}\right]=\left[M^{-1}L^{2}T^{-1}A\right]\)
4
\(\left[\varepsilon _{0}\right]=\left[M^{-1}L^{-3}T^{2}A\right]\)