A bag contains 5 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.
1
\(\dfrac{17}{40}\)
2
\(\dfrac{21}{40}\)
3
\(\dfrac{19}{20}\)
4
\(\dfrac{17}{20}\)
5
\(\dfrac{21}{20}\)