Between 2 O'clock and 3 O'clock, when the times at which the minutes and hour hands be at 15° with each other are 2 hours t1, min. and 2 hours t2 min., then t2 - t1 =
1
\(\frac{{240}}{11} \)
2
\(\frac{{160}}{11} \)
3
\(\frac{{600}}{11} \)
4
\(\frac{{60}}{11} \)