ABCD is a parallelogram where AC and BD are the diagonals. If ∠BAD = 60°, ∠ADB = 90°, then what is BD2 equal to?

1
\(\frac{3}{5}A{B^2}\)
2
\(\frac{3}{4}A{B^2}\)
3
\(\frac{1}{2}A{B^2}\)
4
\(\frac{2}{3}A{B^2}\)

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