A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as kθ2. If its moment of inertia is I then the angular acceleration of the disc is:
1
\(\frac{{\rm{k}}}{{4{\rm{I}}}}{\rm{\theta }}\)
2
\(\frac{{\rm{k}}}{{{\rm{I}}}}{\rm{\theta }}\)
3
\(\frac{{\rm{k}}}{{2{\rm{I}}}}{\rm{\theta }}\)
4
\(\frac{{\rm{2k}}}{{{\rm{I}}}}{\rm{\theta }}\)