If the escape velocity from Earth is given by \(2\sqrt{\frac{GM}{K}}\), where M is the mass of Earth and K is a constant. Then the correct relationship between K and radius of the earth R is-
1
\(R =\frac{K}{2}\)
2
\(R =\frac{K}{\sqrt3}\)
3
R = K
4
R = 2K