In the given figure, TB is a chord which passes through the centre of the circle. PT is a tangent to the circle at the point T on the circle. If PT = 10 cm, PA = 5 cm and AB = x cm, then the radius of the circle is:
1
\(5\sqrt{3} \) cm
2
\(6\sqrt{3} \) cm
3
\(3\sqrt{3} \) cm
4
\(10 \sqrt{3}\) cm