From a point P on a level ground, the angle of elevation of the top of the tower is 30°. If the distance of point P from the foot of the tower is 510 m, then 50% of the height of the tower (in m) is:

1
85
2
\(85\sqrt{3}\)
3
\(150\sqrt{3}\)
4
\(\frac{85\sqrt{3} }{3}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation