Tap T can fill a pot in 4 hours and tap U can fill it in 6 hours. If both the taps are opened on alternative hours and tap T is open first, then in how much time the pot will be full?

1
\(4\frac{1}{2}\)
2
\(3\frac{1}{2}\)
3
\(3\frac{1}{4}\)
4
\(4\frac{2}{3}\)

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