If a cube maximum possible volume is cut off from a solid sphere of diameter d, then the volume of the remaining (waste) material of the sphere would be equal to:
1
\(\frac{{{d^3}}}{3}\left( {\pi - \frac{d}{2}} \right)\)
2
\(\frac{{{d^3}}}{3}\left( {\frac{\pi }{2} - \frac{1}{{\sqrt 3 }}} \right)\)
3
\(\frac{{{d^2}}}{4}\left( {\sqrt 2 - \pi } \right)\)
4
None of these