From the top of a cliff 100-metre high, the angles of depression of the top and bottom of a tower are 45° and 60° respectively. The height of the tower is

1
\(\frac{{100}}{3}\left( {3 - \sqrt 3 } \right)\;{\rm{metre}}\)
2
\(\frac{{100}}{3}\left( {\sqrt 3 - 1} \right)\;{\rm{metre}}\)
3
\(\frac{{100}}{3}\left( {2\sqrt 3 - 1} \right){\rm{metre}}\)
4
\(\frac{{100}}{3}\left( {\sqrt 3 - \sqrt 2 } \right){\rm{metre}}\)
5
Question Not Attempted

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