If \(\sqrt{3}\) tan 2θ − 3 = 0, then find the value of tan θ sec θ − sin θ where 0 < θ < 90°

1
\(\frac{7}{6}\)
2
\(\frac{5}{6}\)
3
\(\frac{2}{3}\)
4
\(\frac{1}{6}\)
5
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