Assume each oil drop consists of a capacitance of C. If combine n drops to form a bigger drop, then the capacitance of bigger drop C' would be

1
C' = \(\frac{2\text{n}^{1/3}}{3}\)C
2
C' = \(\frac{5\text{n}^{1/3}}{4}\)C
3
C' = \(\frac{\text{n}^{1/3}}{5}\)C
4
C' = C⋅n1/3
5
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