\(6\frac{7}{11}+13\frac{15}{22}-7\frac{3}{55}-x=7\frac{13}{110}\), then x is 

1
\(6\frac{5}{55}\)
2
\(20\frac{3}{55}\)
3
\(6\frac{8}{55}\)
4
\(11\frac{5}{55}\)

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