Strain energy stored in a hollow shaft of external diameter (D) and internal diameter (d) when subjected to shear stress (\(\tau\)) is equal to
1
\(\frac{\tau^{2}}{C}\left[\frac{D^{2}+d^{2}}{D}\right] V\)
2
\(\frac{\tau^{2}}{4 C}\left[\frac{D^{2}+d^{2}}{D^2}\right]V\)
3
\(\frac{\tau^{2}}{C}\left[\frac{D^{2}-d^{2}}{D^2}\right]V\)
4
\(\frac{4 \tau^{2}}{C}\left[\frac{D^{2}-d^{2}}{d}\right]V\)
5
Question Not Attempted