Two vessels A and B contain a mixture of alcohol and water such that A contains 25% alcohol and B contains 15% alcohol. Some part of the mixture in vessel A is replaced by an equal quantity of mixture from vessel B. How much quantity of the mixture was replaced if the final mixture vessel is 18% alcohol?

1
\(\frac{5}{7}\)
2
\(\frac{3}{5}\)
3
\(\frac{7}{10}\)
4
\(\frac{6}{7}\)

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