The value of 

\(\frac{4}{6}+\frac{4}{6}+\frac{2}{12}+\frac{4}{6}-4=\)

1
\(-\frac{18}{12}\)
2
\(-\frac{23}{12}\)
3
\(-\frac{25}{12}\)
4
\(-\frac{22}{12}\)

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