If (11x + 8)3 + (2 - x)3 - 27(2x - 5)3 = 9(11x + 8)(x - 2)(2x - 5), then what is the value of \(\sqrt{x^2-36}\) ?

1
\(\frac{9}{2}\)
2
\(\frac{7}{2}\)
3
\(\frac{9}{4}\)
4
\(\frac{7}{4}\)

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