If \(\rm {a}=\vec{i}-2 \vec{j}+\vec{{k}}\), \(\rm {b}=\vec{i}+\vec{{k}}, {c}=2 \vec{j}-\vec{{k}}\), then the area (in sq. units) of a parallelogram with diagonals a + b and b + c will be:
1
\(2 \sqrt{14}\)
2
14
3
\(\frac{\sqrt{14}}{2}\)
4
\(\sqrt{14}\)