\(\int {\frac{{\log x}}{{{{(1 + \log x)}^2}}}\,} dx = \)

1
\( {\frac{{1}}{{{{1 + \log x }}}}\,} +c\)
2
\({\frac{{ x}}{{{{(1 + \log x)}^2}}}\,} +c\)
3
\({\frac{{x}}{{{{1 + \log x}}}}\,}+ c \)
4
\(\frac{1}{{{{(1 + \log x)}^2}}} + c\)

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