defence exam Agniveer Army Technical Mock Test Series 2025 Mathematics Integral Calculus Definite Integrals
\(\mathop \smallint \nolimits_0^1 \frac{{{{\sin }^{ - 1}}{\rm{x}}}}{{\sqrt {1 - {{\rm{x}}^2}} }}{\rm{dx}}\) is equal to?
1
\(\frac{π^2}{2}\)
2
\(\frac{π^2}{4}\)
3
\(\frac{π^2}{8}\)
4
None of the above