If \(\tan ^{ -1 }{ 2x } +\tan ^{ -1 }{ 3x } =\cfrac { \pi }{ 4 }\), then \(x=\)

1
\(-1\)
2
\(\cfrac { 1 }{ 3 }\)
3
\(\cfrac { 1 }{ 6 }\)
4
\(\cfrac { 1 }{ 2 }\)

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