The coordinates of A and B are (1, 2) and (2, 3) respectively. If P lies on AB such that \(\dfrac{PB}{PA}=\dfrac{3}{7}\) the coordinates of P are

1
\(\left(\dfrac{11}{7}, \dfrac{18}{7}\right)\)
2
\(\left(\dfrac{9}{7}, \dfrac{11}{7}\right)\)
3
\(\rm (\dfrac{17}{10}, \dfrac{27}{10})\)
4
\(\left(\dfrac{19}{11}, \dfrac{15}{11}\right)\)

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