If \(\rm a^{\frac{1}{3}}+b^{\frac{1}{3}}+c^{\frac{1}{3}}=0\), then

1
a + b + c = 0
2
(a + b + c)3 = 27abc
3
a + b + c = 3abc
4
a3 + b3 + c3 = 0

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