If A(3, 1, -1), B\(\rm \left(\frac{5}{3},\frac{7}{3}, \frac{1}{3}\right)\), C(2, 2, 1) and D\(\rm \left(\frac{10}{3},\frac{2}{3}, \frac{-1}{3}\right)\) are the vertices of a quadrilateral ABCD, then its area is
1
\(\frac{4\sqrt2}{3}\)
2
\(\frac{5\sqrt2}{3}\)
3
2√2
4
\(\frac{2\sqrt2}{3}\)