Let A and B be two events such that \(\rm P\left( \overline{A\cup B} \right)=\frac{1}{6}\)\(\rm P\left( A\cap B \right)=\frac{1}{4}\) and \(\rm P\left( \overline{A} \right)=\frac{1}{4}\), where A̅ is the complementary event of A. Then A and B are:

1
Equally likely but not independent.
2
Equally likely and mutually exclusive.
3
Mutually exclusive and independent.
4
Independent but not equally likely.

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