If cos θ = cos α cos β, then \(tan(\frac{θ + α}{2}) tan(\frac{θ - α}{2})\) is equal to

1
tan2\(\frac{α}{2}\) 
2
tan2\(\frac{β}{2} \)
3
tan2\(\frac{θ}{2}\)  
4
cot2\(\frac{β}{2}\) 

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