A biased coin with probability p(0 < p < 1) of getting head is tossed until a head appears for the first time. if the probability that the number of tosses required is even is \(\frac{2}{5}\), then p = 

1
\(\frac{1}{4}\)
2
\(\frac{1}{3}\)
3
\(\frac{2}{3}\)
4
\(\frac{3}{4}\)

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