If lines \(\cfrac { x-1 }{ 2 } =\cfrac { y+1 }{ 3 } =\cfrac { z-1 }{ 4 }\) and \(x-3=\cfrac { y-k }{ 2 }\) intersect then the value of \(k\) is

1
\(\cfrac { 13 }{ 4 }\)
2
\(\cfrac { 1 }{ 2 }\)
3
\(\cfrac { 5 }{ 2 }\)
4
\(\cfrac { 7 }{ 2 }\)

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