If the sum of first 'n' natural numbers is \(\frac{n(n+1)}{2}\). Then, what will be the sum of first 'n' terms of the series of alternate positive and negative numbers when 'n' is even?

12 - 22 + 32 - 42 + 52 - ...

I. \(\frac{n(n+1)}{2}\)

II. \(\frac{n^2(n+1)}{2}\)

III. \(\frac{-n(n+1)}{2}\)

Which of the above statement(s) is/are correct?

1
Only I
2
Only III
3
Only II
4
None of these

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